澳大利亚34岁妇女詹妮塔·索·纳阿莫阿纳于7月14日成功产下四胞胎女孩，这是一次极其罕见的自然受孕妊娠 [1]。四个婴儿分别取名艾米丽、哈丽特、凯瑟琳和亚历克莎，均由单个受精卵自然分裂而成 [1]。
医学界对这一事件的罕见程度评价极高 [1]。四胞胎由同一受精卵分裂产生的医学概率约为1500万分之一，而自然受孕四胞胎的总体概率为70万分之一 [1]。参与接生的医生亚历克莎·本德尔表示："我们认为这在澳大利亚从未发生过" [1]。
母亲詹妮塔已有四个孩子，在本次妊娠10周时开始接受医学监测 [1]。妊娠25周时，她被住院观察 [1]。四胞胎在妊娠28周4天时通过剖腹产分娩 [1]。目前，母亲和四个婴儿状况良好，婴儿们正在新生儿重症监护病房接受护理 [1]。
A 34-year-old Australian woman, Janetta Sao Naa Moana, has delivered identical quadruplet girls in what medical experts consider an extraordinarily uncommon natural pregnancy [1]. The four daughters—Emily, Harriet, Catherine, and Alexa—were born on July 14 at Royal Brisbane and Women's Hospital in Queensland [1].
The quadruplets developed from a single fertilized egg that naturally divided, an occurrence with medical odds of approximately 1 in 15 million [1]. While the overall probability of naturally conceiving quadruplets is 1 in 700,000, identical quadruplets from a single embryo represent an exceptionally rarer outcome [1]. According to physician Alexa Bendel, "We believe this has never happened before in Australia's history" [1].
Sao Naa Moana, who already had four children, began receiving medical monitoring at 10 weeks of pregnancy and was hospitalized at 25 weeks [1]. The quadruplets were delivered via cesarean section at 28 weeks and 4 days of gestation [1]. All four infants are currently in neonatal intensive care and are doing well, as is their mother [1].